Post by Nitesh kumar Jha

🚀 Day 38/45 – #SDESheetChallenge Today's Binary Tree problems showed me that every traversal is more than an order of nodes—it's information waiting to be decoded. 🌳 Maximum Path Sum → Used DFS to compute the maximum gain from each node while updating the best path globally. 🧩 Construct Binary Tree from Preorder & Inorder → Used Preorder to identify the root and Inorder to split the tree into left and right subtrees recursively. 🧩 Construct Binary Tree from Postorder & Inorder → Used Postorder to identify the root and Inorder to recursively rebuild the tree from the bottom up. 🧠 Today's takeaway: A traversal isn't just a sequence. It's a blueprint. One traversal tells where to start. Another tells how to divide. And when combined, they reveal the entire tree. Sometimes, the answer isn't about creating something new—it's about reconstructing what already exists from the clues you're given. ✅ Day 38/45 Complete A big thanks to takeUforward for another day of learning and consistency. 🚀 #SDESheetChallenge #TakeUForward #DSA #BinaryTree #TreeTraversal #DFS #StriverSDESheet #LeetCode #ProblemSolving #LearningInPublic